Simplify: a6÷a4
Suppose a2,a3,a4,a5,a6,a7are integers such that 57=a22!+a33!+a44!+a55!+a66!+a77! where 0 ≤ a< j for j= 2,4,5,6,7.
The sum a2+a3+a4+a5+a6+a7 is