Simplify $a (a^{2} + a + 1) + 5$ and find its value for $(i) a = 0, (i i) a = 1 (i i i) a = - 1 .$

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Solution

Given: $a (a^{2} + a + 1) + 5$
a (a²+ a + 1) + 5
⇒ (a × a²)+ (a × a) + (a + 1) + 5
⇒ a³+ a²+ a + 5
Puting a = 0 in a³+ a²+ a + 5
a³+ a²+ a + 5
⇒ 0³ + 0² + 0 + 5
⇒ 5
Puting a = 1 in a³+ a²+ a + 5
a³+ a²+ a + 5
⇒ 1³ + 1² + 1 + 5
⇒ 1 + 1 + 1 + 5
⇒ 8
Puting a = -1 in a³+ a²+ a + 5
a³+ a²+ a + 5
⇒ (-1)³ + (-1)² – 1 + 5
⇒ -1 + 1 – 1 + 5
⇒ 4

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Simplify $a (a^{2} + a + 1) + 5$ and find its value for $a = 0, a = 1 a n d a = - 1$ .

a (a^{2} + a + 1) + 5

Question 4(b)
Simplify : $a (a^{2} + a + 1) + 5$ and find its value for (i) a=0 (ii) a=1 (iii) a=-1.

Simplify $a (a^{2} + a + 1) + 5$ and find its value for (i) $a$ = $0$ , (ii) $a$ = $1$
(iii) $a$ = $- 1$

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