Simplify : (a−b)2+4ab
a2 + b2
(a+b)2
a2 - b2
a2−b2+4ab
To Simplify : (a−b)2+4ab Using the identity, (a−b)2 = a2−2ab+b2 So, (a−b)2+4ab=a2−2ab+b2+4ab =a2+2ab+b2=(a+b)2∵(a+b)2=a2+2ab+b2 Hence, (a−b)2+4ab=(a+b)2
The equation of the circle with center (– a, – b) and radius √a2 – b2 is:
The length of common chord of the circles (x−a)2+y2 =a2 and x2+(y−b)2 = b2 is