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Question

Simplify : (ab)3

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Solution

(ab)2=(ab)(ab)(ab)

=(ab)[a(ab)b(ab)]

=(ab)[a2abab+b2]

=(ab)[a2+b22ab]

=a(a2+b22ab)b(a2+b2+2ab)

=a3+ab22a2bba2b3+2ab2

(ab)3=a2b33ab23a2b

(ab)3=a2b33ab(ab)

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