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Question

Simplify: (a+b)(cd)+(ab)(c+d)+2(ac+bd)

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Solution

Now,
(a+b)(cd)+(ab)(c+d)+2(ac+bd)
=(ac+bcadbd)+(ac+adbcbd)+2(ac+bd)
=(ac+ac+2ac)+(bcbc)+(ad+ad)+(bdbd+2bd)
=4ac.

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