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Question

Simplify (a+b)(cd)+(ab)(c+d)+2(ac+bd)

A
4ac
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B
4ac4bd
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C
4bd
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D
4ac+4bd
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Solution

The correct option is A 4ac
(a+b)(cd)+(ab)(c+d)+2(ac+bd)
=a(cd)+b(cd)+a(c+d)b(c+d)+2(ac+bd)
=acad+bcbd+ac+adbcdb+2ac+2bd
=4ac

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