CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Simplify:
(ab+bc)22ab2c

Open in App
Solution

(ab+bc)22ab2c
=(ab)2+2×ab×bc+(bc)22ab2c
[Using identity (a+b)2=a2+2ab+b2]=a2b2+2ab2c+b2c22ab2c=a2b2+b2c2

flag
Suggest Corrections
thumbs-up
4
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Halves and Quarters
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon