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Question

Simplify and express each of the following in exponential form: (3×72×118)(21×113).


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Solution

Use the appropriate law of exponents

Given: (3×72×118)(21×113)

Factors of 21=7×3

The given expression can be written as

=(3×72×118)(7×3×113)=31-1×72-1×118-3aman=am-n=30×7×115=1×7×115=7×115

Hence, (3×72×118)(21×113)=7×115


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