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Question

Simplify and express each of the following in exponential form:
(i) {(23)4×28}÷212
(ii) (82 × 84) ÷ 83
(iii) 5752×53
(iv) 54×x10y554× x7y4

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Solution

We have
(i) {(23)4 x 28} ÷ 212
= {212 x 28} ÷ 212
= 2(12 + 8) ÷ 212
= 220 ÷ 212
= 2 (20 - 12) = 28

(ii) (82 x 84) ÷ 83
= 8(2 + 4) ÷ 83
= 86 ÷ 83
= 8(6-3) = 83 = (23)3 = 29

(iii) 5752 x 53 = 5(7-2) x 53
= 55 x 53
= 5(5 + 3 ) = 58

(iv) 54 ×x10y554×x7y4 = 5(4-4)×x(10-7)×y(5-4)
= 50×x3×y [since 50 = 1]
= 1×x3y =x3y

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