Simplify and express the answer in exponential form :
$[(4)^{5} \times (4)^{2}] \div (2^{6} \times 2^{4})$

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Solution

$[4^{5} \times 4^{2}] \div (2^{6} \times 2^{4})$
$= [4^{5 + 2}] \div [2^{6 + 4}]$
$= 4^{7} \div 2^{10}$
$= 4^{7} \div 4^{5}$
$= 4^{7 - 5} = 4^{2} = 16$

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