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Byju's Answer
Standard VII
Mathematics
Dividing a Monomial by a Monomial
Simplify and ...
Question
Simplify and express the following in exponential form:
2
3
×
3
4
×
4
3
×
32
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Solution
2
3
×
3
4
×
4
3
×
32
=
2
3
×
3
4
×
2
2
3
×
2
5
=
2
3
+
2
×
3
4
3
×
2
5
=
2
5
×
3
4
3
×
2
5
=
2
5
−
5
×
3
4
−
3
=
2
0
×
3
3
=
1
×
3
3
=
3
3
[
∵
a
m
×
a
v
=
a
m
+
v
]
[
∵
a
m
÷
a
v
=
a
m
−
v
]
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Similar questions
Q.
Question 2(i)
Simplify and express each of the following in exponential form:
(i)
2
3
×
3
4
×
4
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×
32
Q.
Simplify and express each of the following in exponential form:
3
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×
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Q.
Simplify and express in exponential form :
[
(
−
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)
4
×
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÷
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7
Q.
Simplify and express:
2
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3
4
×
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×
32
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Simplify and write the answer in exponential form:
3
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×
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×
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NCERT - Standard VII
Dividing a Monomial by a Monomial
Standard VII Mathematics
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