Simplify and express the result in power notation with positive exponent.

$(3^{- 7} \div 3^{- 10}) \times 3^{- 5}$ is $\frac{1}{(3)^{m}}$
$m$ is

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Solution

$(3^{- 7} \div 3^{- 10}) \times 3^{- 5}$ = $(3^{- 7} \times 3^{- 5}) \div 3^{- 10}$ = $(3)^{(- 7 - 5 + 10)}$ = $3^{(- 2)}$ = $\frac{1}{3^{2}}$

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