Question

Simplify and express the result in the form of a + bi:
${\left(\frac{4i^3-i}{2i+1}\right)}^2$

Answer 1

$(\frac{4i^3-i}{2i+1}{)}^2$

$=(\frac{-5i(1-2i)}{1+4}{)}^2$

$=(2+i{)}^2$

=$4-1+4i$

=$3+4i$