Question

Simplify and give reasons
${\left(\frac{3}{4}\right)}^{-3}$

Answer 1

${\left(\frac{3}{4}\right)}^{-3}{a}^{-n}=\frac{1}{a^n}⟹{\left(\frac{4}{3}\right)}^3{\left(\frac{a}{b}\right)}^n=\frac{a^n}{b^n}⟹\frac{4^3}{3^3}=\frac{64}{27}$