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Question

Simplify and solve the following linear equation.
15(y4)2(y9)+5(y+6)=0
[3 marks]

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Solution

15(y4)2(y9)+5(y+6)=0
15y602y+18+5y+30=0
[1 mark]

18y12=0
18y=12
y=1218
y=23
[1 mark]

To check:
15(y4)2(y9)+5(y+6)=0
15(234)2(239)+5(23+6)=0
15(2123)2(2273)+5(2+183)=0
15×1032×253+5×203=0
50+503+1003=0
50+50+1003=0
50+1503=0
50+50=0
0=0
L.H.S.=R.H.S
Therefore, it is correct.
[1 mark]

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