Question

Simplify and write in exponential form:
$(3^2{)}^5\times (3^4{)}^7$

Answer 1

Using $(a^m{)}^n=a^{mn}$ and $a^m\times a^n=a^{(m+n)}$

$(3^2{)}^5\times (3^4{)}^7=3^{2\times 5}\times 3^{4\times 7}=3^{10}\times 3^{28}=3^{10+28}=3^{38}$