Question

Simplify and write in exponential form:
$4^3\times 4^{-2}\times {16}^2$

• A. $4^3$
• B. $4^4$
• C. $4^5$
• D. $4^6$

Answer 1

The correct option is C

$4^5$

$a^x$ $\times$ $a^y$ = $a^{x+y}$.
Therefore,
$4^3\times 4^{-2}\times {16}^2=4^3\times 4^{-2}\times {\left(\right(4{)}^2)}^2=4^3\times 4^{-2}\times 4^4=4^{3-2+4}=4^5$