Simplify and write in exponential form-43- 4-2- 162

The correct option is D 4^5 Given, 4^3×4^ 2×16^2 = 4^3× 4^ 2× ((4)^2)^2 ∵ (a^m)^n = (a)^m × n ⇒4^3 nbsp; nbsp;× nbsp;4^ 2 nbsp; nbsp;×4^4 ∵ a^x× a^y ...

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Byju's Answer

Standard VII

Mathematics

Power Law

Simplify and ...

Question

Simplify and write in exponential form:
$4^{3} \times 4^{- 2} \times 16^{2}$

$4^{3}$

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$4^{4}$

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$4^{5}$

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$4^{6}$

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Solution

The correct option is C
$4^{5}$

Given, $4^{3} \times 4^{- 2} \times 16^{2}$
$= 4^{3} \times 4^{- 2} \times {((4)^{2})}^{2}$

$∵ (a^{m})^{n} = (a)^{m \times n}$
$\Rightarrow$ $4^{3} \times 4^{- 2} \times 4^{4}$

$∵ a^{x} \times a^{y} = a^{x + y}$
$\Rightarrow 4^{3 - 2 + 4} = 4^{5}$

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Simplify and write in exponential form: 43×4−2×162

The correct option is C 45 Given, 43×4−2×162 =43× 4−2× ((4)2)2 ∵(am)n = (a)m×n ⇒43×4−2×44 ∵ax×ay=ax+y ⇒43−2+4=45

Simplify and write in exponential form:
$4^{3} \times 4^{- 2} \times 16^{2}$

The correct option is C
$4^{5}$

Given, $4^{3} \times 4^{- 2} \times 16^{2}$
$= 4^{3} \times 4^{- 2} \times {((4)^{2})}^{2}$

$∵ (a^{m})^{n} = (a)^{m \times n}$
$\Rightarrow$ $4^{3} \times 4^{- 2} \times 4^{4}$

$∵ a^{x} \times a^{y} = a^{x + y}$
$\Rightarrow 4^{3 - 2 + 4} = 4^{5}$