Question

Simplify and write in exponential form:
$\frac{(-3{)}^5\times 8^3\times 2^5}{3^2\times 4^4}$

Answer 1

$\frac{(-3{)}^5\times 8^3\times 2^5}{3^2\times 4^4}$
$=\frac{(-1{)}^5\times 3^5\times (2^3{)}^3\times 2^5}{3^2\times (2^2{)}^4}$
$=\frac{-1\times 3^5\times 2^9\times 2^5}{3^2\times 2^8}$
$=-1[3^{5-2}\times 2^{9+5-8}]$
$=-1[3^3\times 2^6]$
$=(-3{)}^3\times 2^6$
$=(-27\times 64)$
$=-1728$