Question

Simplify and write in exponential form:
$\frac{9^8\times (x^2{)}^5}{(27{)}^4\times (x^3{)}^2}$

Answer 1

$\frac{9^8\times (x^2{)}^5}{(27{)}^4\times (x^3{)}^2}$
$=\frac{(3^2{)}^8\times x^{2\times 5}}{(3^3{)}^4\times x^{3\times 2}}$
$=\frac{3^{16}\times x^{10}}{3^{12}\times x^6}$
$=3^{16-12}\times x^{10-6}$
$=3^4\times x^4$
$=(3x{)}^4$