Question

Simplify and write in exponential form.
$(\frac{8^2}{8^5}{)}^4\times 8^{-3}$

Answer 1

$(\frac{8^2}{8^5}{)}^4\times 8^{-3}$
$=(8^{2-5}{)}^4\times 8^{-3}$
$=(8^{-3}{)}^4\times 8^{-3}$
$=8^{-12}\times 8^{-3}$
$=8^{-15}$