Question

Simplify and write the answer in the exponential form.

${\left(19\right)}^4\times {\left(19\right)}^2\times 19$

Answer 1

Hint: We know the law of exponents that is powers with same base: $x^a\times x^b=x^{a+b}$

Step 1: Given expression: ${\left(19\right)}^4\times {\left(19\right)}^2\times 19$

Step 2: Solution:

Using the above law:

$$\begin{gathered} {\left(19\right)}^4\times {\left(19\right)}^2\times 19={\left(19\right)}^{4+2+1}\{x^a\times x^b\times x^c=x^{a+b+c}\} \\ ={\left(19\right)}^7 \end{gathered}$$

Hence, ${\left(19\right)}^7$, this is the required exponential form.