Question

Simplify and write the answer in the exponential form.

${\left(m\right)}^2\times {\left(m\right)}^2$

Answer 1

Hint: We know the law of exponents that is powers with same base: $x^a\times x^b=x^{a+b}$

Step 1: Given expression: ${\left(m\right)}^2\times {\left(m\right)}^2$

Step 2: Solution:

Using the above law:

$\begin{array}{rcl}{\left(m\right)}^2\times {\left(m\right)}^2& =& {\left(m\right)}^{2+2};\{x^a\times x^b=x^{a+b}\}\\ & =& {\left(m\right)}^4\end{array}$

${\left(m\right)}^4$, this is the required exponential form.

Hence ${\left(m\right)}^4$, this is the required exponential form.