Question

Simplify and write the following in exponential form : ${\left(3^4\right)}^{-3}-2^0\times {\left(3^2\right)}^4+{\left(2^0\right)}^2$ .

Answer 1

Given that , ${\left(3^4\right)}^{-3}-2^0\times {\left(3^2\right)}^4+{\left(2^0\right)}^2$ .

$={\left(3\right)}^{-3\times 4}-2^0\times {\left(3\right)}^{2\times 4}+{\left(2\right)}^{2\times 0}$

$=3^{-12}-1\times {\left(3\right)}^8+2^0$

$=3^{-12}-3^8+1$

Hence , the required value is $3^{-12}-3^8+1$.