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Byju's Answer
Standard VII
Mathematics
Power of a Power
Simplify 15 ...
Question
Simplify
15
4
×
14
2
21
3
×
10
3
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Solution
The numerator is
15
4
×
14
2
=
(
3
×
5
)
4
×
(
2
×
7
)
2
=
3
4
×
5
4
×
2
2
×
7
2
Similarly the denominator is
21
3
×
10
3
=
(
7
×
3
)
3
×
(
2
×
5
)
3
=
7
3
×
3
3
×
2
3
×
5
3
The given expression is therefore
3
4
×
5
4
×
2
2
×
7
2
7
3
×
3
3
×
2
3
×
5
3
=
3
4
−
3
×
5
4
−
3
×
2
2
−
3
×
7
2
−
3
=
3
×
5
2
×
7
=
15
14
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