Simplify- m 8 p 7 r 12 m 3 r 9 p - p 2 r 3 m 4

The correct option is D m^9p^8r^6 #160; m ^ 8 p ^ 7 r ^ 12 m ^ 3 r ^ 9 p ^ #160;× p ^ 2 r ^ 3 m ^ 4 ⇒ #160; #160; m ^ 12 p ...

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Byju's Answer

Standard VIII

Mathematics

Multiplication of Monomials

Simplify: m...

Question

Simplify: $\frac{m^{8} p^{7} r^{12}}{m^{3} r^{9} p} \times p^{2} r^{3} m^{4}$

m^{5} p^{8} r^{3}

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m^{9} p^{8} r^{7}

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m^{9} p^{7} r^{4}

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m^{9} p^{8} r^{6}

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Solution

The correct option is D $m^{9} p^{8} r^{6}$
$\frac{m^{8} p^{7} r^{12}}{m^{3} r^{9} p} \times p^{2} r^{3} m^{4}$
$\Rightarrow$
$\frac{m^{12} p^{9} r^{15}}{m^{3} r^{9} p^{1}}$
$\Rightarrow$
$m^{9} p^{8} r^{6}$ (option D)

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Similar questions

Q. Simplify

m^{5} \times m^{6}

Q. Show that

1 + \frac{1}{r} + \frac{1}{r^{4}} + \frac{1}{r^{9}} + \frac{1}{r^{16}} + \dots = 1 + \frac{1}{r -} \frac{r}{r^{3} + 1 -} \frac{r^{3}}{r^{5} + 1 -} \frac{r^{5}}{r^{7} + 1 -} \dots

$P (x) = (x - 1) (x - 2) (x - 3) (x - 4) (x - 5) (x - 6)$ .
What is the value of $P (11) \times P (10) \times P (9) \times P (8) \times P (7) \times P (6)$ ?

Q. Let

P

be a

2 \times 2

matrix such that

[\begin{matrix} 1 & 0 \end{matrix}] P = - \frac{1}{\sqrt{2}} [\begin{matrix} 1 & 1 \end{matrix}]

and

[\begin{matrix} 0 & 1 \end{matrix}] P = \frac{1}{\sqrt{2}} [\begin{matrix} - 1 & 1 \end{matrix}]

0

and

I

denote the zero and identity matrices of order

2

, respectively, then which of the following options is correct ?

Show that (p - 1) is a factor of p^{10} + p^{8} + p^{6} - p^{4} - p^{2} - 1

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Simplify: m8p7r12m3r9p×p2r3m4

The correct option is D m9p8r6 m8p7r12m3r9p×p2r3m4⇒ m12p9r15m3r9p1⇒ m9p8r6 (option D)

Simplify: $\frac{m^{8} p^{7} r^{12}}{m^{3} r^{9} p} \times p^{2} r^{3} m^{4}$

The correct option is D $m^{9} p^{8} r^{6}$
$\frac{m^{8} p^{7} r^{12}}{m^{3} r^{9} p} \times p^{2} r^{3} m^{4}$
$\Rightarrow$
$\frac{m^{12} p^{9} r^{15}}{m^{3} r^{9} p^{1}}$
$\Rightarrow$
$m^{9} p^{8} r^{6}$ (option D)