Question

Simplify $\cos {70}^{\circ }{12}^{\prime }+\tan {48}^{\circ }{54}^{\prime }$

Answer 1

From the cosine and tangent tables, we find
$\cos {70}^{\circ }{12}^{\prime }=0.3387,\tan {48}^{\circ }{54}^{\prime }=1.1463$
$\therefore \cos {70}^{\circ }{12}^{\prime }+\tan {48}^{\circ }{54}^{\prime }=0.3387+1.1463=1.4850$