The correct option is A 3√(6) 1/2√(243) √(27/4) =√(243/4) √(27/4)=√(243 27/4) =√(216/4)=√(54)=3√(6) ...

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Byju's Answer

Standard IX

Mathematics

Geometrical Method to Find Square Root of a Number

Simplify: 1...

Question

Simplify: $\frac{1}{2} \sqrt{243} - \sqrt{\frac{27}{4}}$

3 \sqrt{6}

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4 \sqrt{2}

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3 \sqrt{2}

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2 \sqrt{3}

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Solution

The correct option is A $3 \sqrt{6}$
$\frac{1}{2} \sqrt{243} - \sqrt{\frac{27}{4}}$
$= \sqrt{\frac{243}{4}} - \sqrt{\frac{27}{4}} = \sqrt{\frac{243 - 27}{4}}$
$= \sqrt{\frac{216}{4}} = \sqrt{54} = 3 \sqrt{6}$

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Similar questions

Simplify
$\frac{(0.3)^{\frac{1}{3}} {(\frac{1}{27})}^{\frac{1}{4}} (9)^{\frac{1}{6}} (0.81)^{\frac{2}{3}}}{(0.9)^{\frac{2}{3}} (3)^{- \frac{1}{2}} {(\frac{1}{3})}^{- 2} (243)^{- \frac{1}{4}}}$

Simplify $\frac{4}{{(216)}^{- 2 / 3}} + \frac{1}{{(256)}^{- 3 / 4}} + \frac{2}{{(243)}^{- 1 / 5}}$

Q. Simplify:

\frac{3}{216^{- 2 / 3}} + \frac{2}{256^{- 3 / 4}} + \frac{2}{243^{- 1 / 5}}

Q. Simplify :

\frac{{\sqrt[4]{(625)^{- 3}} \times \sqrt[5]{0.00001} \times \sqrt[3]{729} \times \sqrt[3]{(0.008)^{- 2}}}}{{\sqrt[5]{243} \times \sqrt[3]{(125)^{- 2}}}}

Q. Simplify:

5 \sqrt{3} + 2 \sqrt{27} + 4 \sqrt{\frac{1}{3}}

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Simplify: 12√243−√274

The correct option is A 3√612√243−√274=√2434−√274=√243−274=√2164=√54=3√6

Simplify: $\frac{1}{2} \sqrt{243} - \sqrt{\frac{27}{4}}$

The correct option is A $3 \sqrt{6}$
$\frac{1}{2} \sqrt{243} - \sqrt{\frac{27}{4}}$
$= \sqrt{\frac{243}{4}} - \sqrt{\frac{27}{4}} = \sqrt{\frac{243 - 27}{4}}$
$= \sqrt{\frac{216}{4}} = \sqrt{54} = 3 \sqrt{6}$