Question

Simplify :$\frac{1}{3}(-2p+6q-9r)-\frac{1}{6}(-4p-18q+24r)=$

• A. $-\frac{4}{3}p$
• B. $5q$
• C. $-7r$
• D. $5q-7r$

Answer 1

The correct option is D $5q-7r$

$\frac{1}{3}(-2p+6q-9r)-\frac{1}{6}(-4p-18q+24r)$

$=-\frac{2p}{3}+\frac{6q}{3}-\frac{9r}{3}+\frac{4p}{6}+\frac{18q}{6}-\frac{24r}{6}$

$=-\frac{2p}{3}+2q-3r+\frac{2p}{3}+3q-4r$

$=-\frac{2p}{3}+\frac{2p}{3}+2q+3q-3r-4r$

$=5q-7r$