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Byju's Answer
Standard IX
Mathematics
Operations on Rational and Irrational Numbers
Simplify 17...
Question
Simplify
1
7
+
4
√
3
+
1
2
+
√
5
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Solution
The rationalising factor of
7
+
4
√
3
is
7
−
4
√
3
and the rationalising factor of
2
+
√
5
is
2
−
√
5
.
=
1
7
+
4
√
3
+
1
2
+
√
5
=
1
7
+
4
√
3
×
7
−
4
√
3
7
−
4
√
3
+
1
2
+
√
5
×
2
−
√
5
2
−
√
5
=
7
−
4
√
3
49
−
48
+
2
−
√
5
(
4
−
5
)
=
7
−
4
√
3
1
+
2
−
√
5
(
−
1
)
=
7
−
4
√
3
−
2
+
√
5
=
5
−
4
√
3
+
√
5
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