Question

Simplify:
$\frac{1-\cos 2x}{1+\cos 2x}$

Answer 1

We have, $\frac{1-\cos 2x}{1+\cos 2x}$

[ Since $1-\cos 2x=2{\sin }^{2}x$ and $1+\cos 2x=2{\cos }^{2}x$]

$\frac{1-\cos 2x}{1+\cos 2x}$$=\frac{2{\sin }^{2}x}{2{\cos }^{2}x}$

$\frac{1-\cos 2x}{1+\cos 2x}$$={\tan }^{2}x$.