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Question

Simplify:
1+12112+47(25+310) of ⎜ ⎜12+1312+13⎟ ⎟

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Solution

1+12112+47(25+310)×⎜ ⎜ ⎜12+1312+13⎟ ⎟ ⎟

=31+47(20+1550)×1=3+47(3550)

=3+410=3+25=175

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