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Byju's Answer
Standard IX
Mathematics
Algebraic Identities
Simplify: 15...
Question
Simplify:
155
×
155
×
155
−
55
×
55
×
55
155
×
155
+
155
×
55
+
55
×
55
A
0
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B
100
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C
210
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D
n
o
n
e
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Solution
The correct option is
B
100
We solve the given expression
155
×
155
×
155
−
55
×
55
×
55
155
×
155
+
155
×
55
+
55
×
55
as shown below:
155
×
155
×
155
−
55
×
55
×
55
155
×
155
+
155
×
55
+
55
×
55
=
(
155
)
3
−
(
55
)
3
(
155
)
2
+
(
155
×
55
)
+
(
55
)
2
=
(
155
−
55
)
[
(
155
)
2
+
(
155
×
55
)
+
(
55
)
2
]
(
155
)
2
+
(
155
×
55
)
+
(
55
)
2
(
∵
x
3
−
y
3
=
(
x
−
y
)
(
x
2
+
y
2
+
x
y
)
)
=
155
−
55
=
100
Hence,
155
×
155
×
155
−
55
×
55
×
55
155
×
155
+
155
×
55
+
55
×
55
=
100
Suggest Corrections
4
Similar questions
Q.
Simplify:
(i)
173
×
173
×
173
+
127
×
127
×
127
173
×
173
-
173
×
127
+
127
×
127
(ii)
155
×
155
×
155
-
55
×
55
×
55
155
×
155
+
155
×
55
+
55
×
55
(iii)
1
.
2
×
1
.
2
×
1
.
2
-
0
.
2
×
0
.
2
×
0
.
2
1
.
2
×
1
.
2
+
1
.
2
×
0
.
2
+
0
.
2
×
0
.
2