Question

Simplify:$\frac{16}{39}+\frac{9}{-26}$

Answer 1

We have $\frac{16}{39}+\frac{9}{-26}=\frac{16}{39}+\frac{-9}{26}$

Now, the L.C.M of $39$ and $26$ is $78$

$\therefore$ Rewriting $\frac{16}{39}$ and $\frac{-9}{26}$ in such a way that they have the same denominator $78$

$\frac{16}{39}=\frac{16\times 2}{39\times 2}=\frac{32}{78}$

$\frac{-9}{26}=\frac{-9\times 3}{26\times 3}=\frac{-27}{78}$

$\therefore \frac{16}{39}+\frac{-9}{26}=\frac{32}{78}+\frac{-27}{78}=\frac{32-27}{78}=\frac{5}{78}$