Question

Simplify:

$\frac{2^3\times 3\times 4}{3^2\times 32}$

Answer 1

We have to find the value of $\frac{2^3\times 3\times 4}{3^2\times 32}$

$\frac{2^3\times 3\times 4}{3^2\times 32}$$=\frac{2^3\times 3\times 2^2}{3^2\times 2^5}$

$\frac{2^3\times 3\times 4}{3^2\times 32}$$=\frac{2^5\times 3}{3^2\times 2^5}$

$\frac{2^3\times 3\times 4}{3^2\times 32}$$=\frac{1}{3^{2-1}}$

$\frac{2^3\times 3\times 4}{3^2\times 32}$$=\frac{1}{3}$.