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Question

Simplify 2i+3i3+4i4+5i5 in the form of a+ib & represent graphically & find modulus & amplitude.

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Solution

Given 2i+3i3+4i4+5i5=a+ib
i2=1 i3=i
i4=1 i5=i
2×2i+3(i)+4+5i=a+ib
2i+3i+45i=a+ib
44i=a+ib
a=4, b=4


|a+ib|=42+42=42
arg(a+ib)=tan(44) ( as it is 4th quadrant )
arg(a+ib)=π4
Hence, the answer is π4.


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