Simplify- 3 216 - 2 - 3 - 2 256 - 3 - 4 - 2 243 - 1 - 5

3/216^ 2/3 +2/256^ 3/4 + 2/(243^ 1/5) #160; using 1/a^m = a^ m 3. ((216)^1/3)^2 + 2 ((256)^1/4)^3 + 2.(243)^1/5 ⇒ #160; 3. (6)^2+ 2 (4) ...

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Byju's Answer

Standard XII

Mathematics

Integration by Partial Fractions

Simplify: 3...

Question

Simplify: $\frac{3}{216^{- 2 / 3}} + \frac{2}{256^{- 3 / 4}} + \frac{2}{243^{- 1 / 5}}$

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Solution

$\frac{3}{216^{- 2 / 3}} + \frac{2}{256^{- 3 / 4}} + \frac{2}{(243^{- 1 / 5})}$ using $\frac{1}{a^{m}} = a^{- m}$
$3. ((216)^{1 / 3})^{2} + 2 ((256)^{1 / 4})^{3} + 2. (243)^{1 / 5}$
$\Rightarrow 3. (6)^{2} + 2 (4)^{3} + 2.3$
$\Rightarrow 3. 36 + 2 \times 64 + 6$
$\Rightarrow 108 + 128 + 6 = 242$

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Similar questions

Simplify
$\frac{(0.3)^{\frac{1}{3}} {(\frac{1}{27})}^{\frac{1}{4}} (9)^{\frac{1}{6}} (0.81)^{\frac{2}{3}}}{(0.9)^{\frac{2}{3}} (3)^{- \frac{1}{2}} {(\frac{1}{3})}^{- 2} (243)^{- \frac{1}{4}}}$

Q. Simplify:

(\frac{- 1}{3} \times \frac{5}{4}) + [\frac{3}{5} \div (\frac{1}{2} - \frac{1}{4})]

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\frac{2}{3} + (\frac{- 4}{5}) + \frac{1}{4} + (\frac{- 2}{3}) + (\frac{- 11}{5})

Q. Simplify:

(\begin{matrix} \frac{- 3}{2} \times \frac{4}{5} \end{matrix}) + (\begin{matrix} \frac{9}{5} \times \frac{- 10}{3} \end{matrix}) - (\begin{matrix} \frac{1}{2} \times \frac{3}{4} \end{matrix})

Q. Simplify

[{(\frac{1}{3})}^{- 3} - {(\frac{1}{4})}^{- 2}] \div {(\frac{1}{5})}^{- 3}

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Simplify: 3216−2/3+2256−3/4+2243−1/5

3216−2/3+2256−3/4+2(243−1/5) using 1am=a−m3.((216)1/3)2+2((256)1/4)3+2.(243)1/5⇒3.(6)2+2(4)3+2.3⇒3.36+2×64+6 ⇒108+128+6=242

Simplify: $\frac{3}{216^{- 2 / 3}} + \frac{2}{256^{- 3 / 4}} + \frac{2}{243^{- 1 / 5}}$

$\frac{3}{216^{- 2 / 3}} + \frac{2}{256^{- 3 / 4}} + \frac{2}{(243^{- 1 / 5})}$ using $\frac{1}{a^{m}} = a^{- m}$
$3. ((216)^{1 / 3})^{2} + 2 ((256)^{1 / 4})^{3} + 2. (243)^{1 / 5}$
$\Rightarrow 3. (6)^{2} + 2 (4)^{3} + 2.3$
$\Rightarrow 3. 36 + 2 \times 64 + 6$
$\Rightarrow 108 + 128 + 6 = 242$