Question

Simplify : $\frac{3^5{2}^2{7}^3}{7^2{3}^3{2}^4}$

Answer 1

Given that,

Let $a=\frac{3^5{2}^2{7}^3}{7^2{3}^3{2}^4}$

$=\frac{3^2.7}{2^2}$

$a=\frac{63}{4}$

$\therefore \frac{3^5{2}^2{7}^3}{7^2{3}^3{2}^4}=\frac{63}{4}$