Question

Simplify:
$\frac{3\times 7^2\times {11}^8}{21\times {11}^3}$

Answer 1

$\frac{3\times 7^2\times {11}^8}{21\times {11}^3}$

$=\frac{3\times 7^2\times {11}^8}{3\times 7\times {11}^3}$

$=3^{1-1}\times 7^{2-1}\times {11}^{8-3}$ [Since, $\frac{a^m}{a^n}=a^{m-n}$]

$=3^0\times 7^1\times {11}^5$

$=7\times {11}^5$

$=7\times 1,61,051=11,27,357$