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Question

Simplify: 3a13a3a+1×a3a1

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Solution

given, 3a13a3a+1×a3a1

=9a213a3a+1×a3a1

=9a213a(3a+1)×a3a1

=(3a+1)(3a1)3a(3a+1)×a3a1

=a(3a+1)(3a1)3a(3a+1)(3a1)

=13

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