Applying the identity in 4[m2+(2n)2−2×m×2n]2(m−2n).
4[m2+(2n)2−2×m×2n]2(m−2n)=4(m−2n)22(m−2n)
=2(m−2n)
=2m−4n
Simplify:
2{m−3(n+¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯m−2n)}
Simplify 16*2n+1-4*2n/16*2n/1*2n+2-2*2n+1