Question

Simplify $\frac{9^3\times 27\times t^4}{(3{)}^2\times (3{)}^4\times t^2}$

Answer 1

$\frac{9^3\times 27\times t^4}{(3{)}^2\times (3{)}^4\times t^2}$

$=\frac{729\times 27\times t^4}{9\times 81\times t^2}$

$=\frac{19683\times t^4}{729\times t^2}$

$=27\times t^2$