Simplify : $\frac{{(\frac{1}{x})}^{- 1}}{{(\frac{1}{x})}^{3}}$

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Solution

We know that

$a^{m} \div a^{n} = a^{m - n}$

$\frac{{(\frac{1}{x})}^{- 1}}{{(\frac{1}{x})}^{3}} = {(\frac{1}{x})}^{- 1 - 3}$

$= {(\frac{1}{x})}^{- 1 - 3} = {(\frac{1}{x})}^{- 4} = x^{4}$

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