We have,
√2003(−20√3)2003
=√2003√(−20√3)√2003√2003
=√(−20√3)√2003
= ⎷−20√32003
=√−3√310
=√−3√3√10×√10√10
=√−30√310
Simplify:
3√45 - √125 + √200 - √50
2√30/√6 - 3√140/√28 + √55/√99
√72 + √800 - √18