Question

Simplify $\frac{x}{\sqrt{x+4}},x>0$

Answer 1

given $\frac{x}{\sqrt{x+4}}$

rationalize above

$\frac{\frac{x}{\sqrt{x+4}}}{\frac{\sqrt{x+4}}{\sqrt{x+4}}}$

$=\frac{x\sqrt{x+4}}{x+4}$