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Byju's Answer
Standard VIII
Mathematics
Factorisation Using Algebraic Identities
Simplify :xx...
Question
Simplify
:
x
x
−
y
−
y
x
+
y
−
2
x
y
x
2
−
y
2
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Solution
x
x
−
y
−
y
x
+
y
−
2
x
y
x
2
−
y
2
=
x
(
x
+
y
)
−
y
(
x
−
y
)
−
2
x
y
x
2
−
y
2
=
x
2
+
x
y
−
x
y
+
y
2
−
2
x
y
x
2
−
y
2
=
x
2
+
y
2
−
2
x
y
x
2
−
y
2
=
(
x
−
y
)
2
(
x
−
y
)
(
x
+
y
)
=
x
−
y
x
+
y
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0
Similar questions
Q.
Let
x
≠
±
y
. Evaluate :
x
2
−
y
2
x
2
+
2
x
y
+
y
2
:
x
−
y
x
+
y
Q.
Simplify and express the results in simplest form :
√
x
2
−
y
2
+
x
√
x
2
+
y
2
+
y
+
√
x
2
+
y
2
−
y
x
−
√
x
2
−
y
2
Q.
Express the following as rational expression.
x
x
−
y
+
y
x
+
y
+
2
x
y
y
2
−
x
2
Q.
Factorize:
x
2
+
y
2
+
x
+
y
+
2
x
y
Q.
If
u
=
tan
−
1
(
x
3
+
y
3
x
−
y
)
,
then
x
2
∂
2
u
∂
x
2
+
2
x
y
∂
2
u
∂
x
∂
y
+
y
2
∂
2
u
∂
y
2
=
?
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