Question

Simplify $\frac{y^3-6y^2+3y+10}{y^2-10y+25}$, given that $y\ne 5$

• A. $\frac{y^2-y+2}{y+5}$
• B. $\frac{y^2-y-2}{y-5}$
• C. $\frac{y^2+y-2}{y+5}$
• D. $\frac{y^2+y-2}{y-5}$
• E. $\frac{y^2-y+2}{y-5}$

Answer 1

The correct option is B $\frac{y^2-y-2}{y-5}$

The value of $\frac{y^3-6y^2+3y+10}{y^2-10y+25}$

$=\frac{(y-5)(y^2-y-2)}{{(y-5)}^2}$

$=\frac{y^2-y-2}{y-5}$