Question

Simplify : $48x^2{y}^4÷(-8{xy}^2)$

• A. $8x{y}^3$
• B. $8xy$
• C. $6x{y}^2$
• D. $-6x{y}^2$

Answer 1

Answer: (D)

$-6x{y}^2$

$48x^2{y}^4÷(-8{xy}^2)=\frac{48x^2{y}^4}{-8{xy}^2}$

= $\frac{6\times 8\times x^2{y}^4}{-8\times x{y}^2}$

= $-6x^{2-1}{y}^{4-2}$

=$-6x{y}^2$