Question

Simplify: $(64{)}^{-\frac{2}{3}}\times {\left(\frac{1}{4}\right)}^{-3}$

• A. $4$
• B. $\frac{1}{4}$
• C. $1$
• D. $16$

Answer 1

Answer: (A)

$4$

${\left(64\right)}^{-\frac{2}{3}}\times {\left(\frac{1}{4}\right)}^{-3}={\left(4^3\right)}^{-\frac{2}{3}}\times {\left(\frac{1}{4}\right)}^{-3}$

$=4^{-2}\times \frac{1}{4^{-3}}=4$