Question

Simplify: $9(a^4{b}^6-a^6{b}^4)÷3a^4{b}^4$

• A. $3(b-a)$
• B. $3(a-b)$
• C. $3(a^2-b^2)$
• D. $3(b^2-a^2)$

Answer 1

The correct option is D $3(b^2-a^2)$

$9(a^4{b}^6-a^6{b}^4)÷3a^4{b}^4=\frac{9(a^4{b}^6-a^6{b}^4)}{3a^4{b}^4}$

$=\frac{9a^4{b}^4(b^2-a^2)}{3a^4{b}^4}$

$=3(b^2-a^2)$